Paper detail

Tensor product of left polaroid operators

A Banach space operator $T\in B(X)$ is left polaroid if for each $λ\in\hbox{iso}σ_a(T)$ there is an integer $d(λ)$ such that asc $(T-λ)=d(λ)<\infty$ and $(T-λ)^{d(λ)+1}X$ is closed; $T$ is finitely left polaroid if asc $(T-λ)<\infty$, $(T-λ)X$ is closed and $\dim(T-λ)^{-1}(0)<\infty$ at each $λ\in\hbox{iso }σ_a(T)$. The left polaroid property transfers from $A$ and $B$ to their tensor product $A\otimes B$, hence also from $A$ and $B^*$ to the left-right multiplication operator $τ_{AB}$, for Hilbert space operators; an additional condition is required for Banach space operators. The finitely left polaroid property transfers from $A$ and $B$ to their tensor product $A\otimes B$ if and only if $0\not\in\hbox{iso}σ_a(A\otimes B)$; a similar result holds for $τ_{AB}$ for finitely left polaroid $A$ and $B^*$.

preprint2014arXivOpen access
0citations
0reviews
0saves
Nocode
Nodataset
0institutions

Next steps

Decide what to do with this paper

Use like or dislike for the fast social read. The more specific scholarly feedback stays available below when needed.

Log in to curate

Reading frame

Keep the important context close to the paper

Keep the important signals around this paper in one place: votes, save state, collection context, reviews and the metadata you need before deciding what to do next.

Institutions

Add specific reaction

Move through the context

Research map

Open full explorer

Move through nearby people, institutions, topics and adjacent work without leaving the paper page.

Building this map preview

BZPEER is loading the nearby papers, people, topics and institutions for this page.

Structured reviews

0 review(s)

ContributeLeave structured feedbackUse the review template when you have a concrete strength, concern or method question.Open review form

No structured reviews yet. High-signal critique starts here.

Work discussion

0 comment(s)

DiscussAdd a high-signal commentKeep quick notes, caveats and replication pointers separate from formal reviews.Open comment form

No discussion yet. The first strong comment sets the tone.