Homomorphisms into a simple Z-stable C*-Algebras

preprint2012arXivOpen access

Abstract

Let AA and BB be unital separable simple amenable \CA s which satisfy the Universal Coefficient Theorem. Suppose {that} AA and BB are Z\mathcal Z-stable and are of rationally tracial rank no more than one. We prove the following: Suppose that ϕ,ψ:A→Bϕ, ψ: A\to B are unital {monomorphisms}. There exists a sequence of unitaries {un}⊂B\{u_n\}\subset B such that $$ \lim_{n\to\infty} u_n^*ϕ(a) u_n=ψ(a)\tforal a\in A, $$ if and only if $$ [ϕ]=[ψ]\,\,\,\text{in}\,\,\, KL(A,B), ϕ_{\sharp}=ψ_{\sharp}\andeqnϕ^‡=ψ^‡, $$ where $ϕ_{\sharp}, ψ_{\sharp}: \aff(T(A))\to \aff(T(B))$ and ϕ‡,ψ‡:U(A)/CU(A)→U(B)/CU(B)ϕ^‡, ψ^‡: U(A)/CU(A)\to U(B)/CU(B) are {the} induced maps and where T(A)T(A) and T(B)T(B) are tracial state spaces of AA and B,B, and CU(A)CU(A) and CU(B)CU(B) are closure of {commutator} subgroups of unitary groups of AA and B,B, respectively. We also show that this holds for some AH-algebras A.A. {Moreover, if κ∈KL(A,B)κ\in KL(A,B) preserves the order and the identity, $λ: \aff(\tr(A))\to \aff(\tr(B))$ is a continuous affine map and γ:U(A)/CU(A)→U(B)/CU(B)γ: U(A)/CU(A)\to U(B)/CU(B) is a \hm\, which are compatible, we also show that there is a unital \hm\, ϕ:A→Bϕ: A\to B so that ([ϕ],ϕ♯,ϕ‡)=(κ,λ,γ),([ϕ],ϕ_{\sharp},ϕ^‡)=(κ, λ, γ), at least in the case that K1(A)K_1(A) is a free group,

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