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Unitary equivalence of proper extensions of a symmetric operator and the Weyl function

Let $A$ be a densely defined simple symmetric operator in $\gH$, let $Π=\bt$ be a boundary triplet for $A^*$ and let $M(\cd)$ be the corresponding Weyl function. It is known that the Weyl function $M(\cd)$ determines the boundary triplet $Π$, in particular, the pair ${A,A_0}$, where $A_0:= A^*\lceil\ker\G_0 (= A^*_0)$, uniquely up to unitary similarity. At the same time the Weyl function corresponding to a boundary triplet for a dual pair of operators defines it uniquely only up to weak similarity. In this paper we consider symmetric dual pairs ${A,A}$ generated by $A\subset A^*$ and special boundary triplets $\wtΠ$ for ${A,A}$. We are interested whether the result on unitary similarity remains valid provided that the Weyl function corresponding to $\wtΠ$ is $\wt M(z)= K^*(B-M(z))^{-1} K,$ where $B$ is some non-self-adjoint bounded operator in $\cH$. We specify some conditions in terms of the operators $A_0$ and $A_B= A^*\lceil \ker(\G_1-B\G_0)$, which determine uniquely (up to unitary equivalence) the pair ${A,A_B}$ by the Weyl function $\wt M(\cd)$. Moreover, it is shown that under some additional assumptions the Weyl function $M_Π(\cdot)$ of the boundary triplet $Π$ for the dual pair $\DA$ determines the triplet $Π$ uniquely up to unitary similarity. We obtain also some negative results demonstrating that in general the Weyl function $\wt M(\cd)$ does not determine the operator $A_B$ even up to similarity.