Abstract
The congruence subgroup problem for a finitely generated group asks whether is injective, or more generally, what is its kernel ? Here denotes the profinite completion of . In this paper we first give two new short proofs of two known results (for and ) and a new result for : 1. when is the free group on two generators. 2. when is the free metabelian group on generators, and is the free profinite group on generators. 3. contains . Results 2. and 3. should be contrasted with an upcoming result of the first author showing that is abelian for .
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