The complete $L^q$-spectrum and large deviations for return times for equilibrium states with summable potentials

Let $(X_k)_{k\geq 0}$ be a stationary and ergodic process with joint distribution $μ$ where the random variables $X_k$ take values in a finite set $\mathcal{A}$. Let $R_n$ be the first time this process repeats its first $n$ symbols of output. It is well-known that $\frac{1}{n}\log R_n$ converges almost surely to the entropy of the process. Refined properties of $R_n$ (large deviations, multifractality, etc) are encoded in the return-time $L^q$-spectrum defined as $\mathcal{R}(q)=\lim_n\frac{1}{n}\log\int R_n^q \,dμ\quad (q\in\mathbb{R})$ provided the limit exists. We consider the case where $(X_k)_{k\geq 0}$ is distributed according to the equilibrium state of a potential $φ:\mathcal{A}^{\mathbb{N}}\to\mathbb{R}$ with summable variation, and we prove that $\mathcal{R}(q) = \begin{cases} P((1-q)φ) & \text{for}\;\; q\geq q_φ^*\\ \sup_η\int φ\, dη& \text{for}\;\; q<q_φ^{*} \end{cases}$ where $P((1-q)φ)$ is the topological pressure of $(1-q)φ$, the supremum is taken over all shift-invariant measures, and $q_φ^*$ is the unique solution of $P((1-q)φ) =\sup_η\int φ\, dη$. Unexpectedly, this spectrum does not coincide with the $L^q$-spectrum of $μ_φ$, which is $P((1-q)φ)$, and does not coincide with the waiting-time $L^q$-spectrum in general. In fact, the return-time $L^q$-spectrum coincides with the waiting-time $L^q$-spectrum if and only if the equilibrium state of $φ$ is the measure of maximal entropy. As a by-product, we also improve the large deviation asymptotics of $\frac{1}{n}\log R_n$.

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