Abstract
Let -1\leq B<A\leq 1. Condition on β, is determined so that 1+βzp'(z)/p^k(z)\prec(1+Az)/(1+Bz)\;(-1<k\leq3) implies p(z)\prec \sqrt{1+z}. Similarly, condition on βis determined so that 1+βzp'(z)/p^n(z) or p(z)+βzp'(z)/p^n(z)\prec\sqrt{1+z}\;(n=0, 1, 2) implies p(z)\prec(1+Az)/(1+Bz) or \sqrt{1+z}. In addition to that condition on βis derived so that p(z)\prec(1+Az)/(1+Bz) when p(z)+βzp'(z)/p(z)\prec\sqrt{1+z}. Few more problems of the similar flavor are also considered.
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