Abstract
On a convex surface , the antipodal map associates to a point the set of farthest points from , with respect to the intrinsic metric. is called a Steinhaus surface if is a single-valued involution. We prove that any convex polyhedron has an open and dense set of points admitting a unique antipode , which in turn admits a unique antipode , distinct from . In particular, no convex polyhedron is Steinhaus.
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