Simultaneous Explanation of the RKR_K and R(D(∗))R(D^{(*)}) Puzzles

preprint2015arXivOpen access

Abstract

At present, there are several hints of lepton flavor non-universality. The LHCb Collaboration has measured RK≡B(B+→K+μ+μ−)/B(B+→K+e+e−)R_K\equiv{\cal B}(B^+ \to K^+ μ^+ μ^-)/{\cal B}(B^+ \to K^+ e^+ e^-), and the BaBar Collaboration has measured R(D(∗))≡B(Bˉ→D(∗)+τ−νˉτ)/B(Bˉ→D(∗)+ℓ−νˉℓ)R(D^{(*)}) \equiv {\cal B}({\bar B} \to D^{(*)+} τ^- {\barν}_τ) / {\cal B}({\bar B} \to D^{(*)+} \ell^- {\barν}_\ell) (ℓ=e,μ\ell = e,μ). In all cases, the experimental results differ from the standard model predictions by 2-3σσ. Recently, an explanation of the RKR_K puzzle was proposed in which new physics (NP) generates a neutral-current operator involving only third-generation particles. Now, assuming the scale of NP is much larger than the weak scale, this NP operator must be made invariant under the full SU(3)C×SU(2)L×U(1)YSU(3)_C \times SU(2)_L \times U(1)_Y gauge group. In this Letter, we note that, when this is done, a new charged-current operator can appear, and this can explain the R(D(∗))R(D^{(*)}) puzzle. A more precise measurement of the double ratio R(D)/R(D∗)R(D)/R(D^*) can rule out this model.

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