Perfectly packing a square by squares of nearly harmonic sidelength

preprint2022arXivOpen access

Abstract

A well known open problem of Meir and Moser asks if the squares of sidelength 1/n1/n for n≥2n \geq 2 can be packed perfectly into a square of area ∑n=2∞1n2=π26−1\sum_{n=2}^\infty \frac{1}{n^2} = \frac{π^2}{6}-1. In this paper we show that for any 1/2<t<11/2 < t < 1, and any n0n_0 that is sufficiently large depending on tt, the squares of sidelength n−tn^{-t} for n≥n0n \geq n_0 can be packed perfectly into a square of area ∑n=n0∞1n2t\sum_{n=n_0}^\infty \frac{1}{n^{2t}}. This was previously known (if one packs a rectangle instead of a square) for 1/2<t≤2/31/2 < t \leq 2/3 (in which case one can take n0=1n_0=1).

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