Pauli blocking and entanglement solve KπKπ puzzle. CP violation in Bo→KπB^o \rightarrow Kπ; not in B±→KπB^{\pm} \rightarrow Kπdecays

preprint2012arXivOpen access

Abstract

New data analysis with Pauli blocking and entanglement explains CP violation in Bo→KπB^o\rightarrow Kπ decays, absence in B±→KπB^{\pm} \rightarrow Kπ decays and predicts unexpected contrast between pure I=1/2 in individual B±B^{\pm} and BoB^o final states and I=1/2 violation in relations between them. Analysis of B→KπB\rightarrow Kπ data predicts these observed isospin relations and explains dependence on spectator quark flavor. B+→KπB^+ \rightarrow Kπ tree diagram bˉu→sˉuuˉu\bar b u\rightarrow \bar s u \bar u u has two identical uu quarks from weak vertex and spectator. The Pauli principle requires these quarks at short distances to have wave functions antisymmetric in color or spin. The eigenvalues of conserved symmetries remain entangled in a final state of two separated mesons. This Pauli entanglement suppresses tree-penguin interference and CP violation in B+B^+ decay but not in BoB^o decay with spectator dd quark. The four-body wave function must have two antiquarks with the same symmetry combining with two u-quarks to fragment into a two-pseudoscalar-meson state even under charge conjugation with angular momentum zero. It is classified in the 27-dimensional representation of flavor SU(3) with isospin I=2 for the ππππ state and V spin V=2 for the corresponding strange state which is linear combination of KπKπ and Kη8Kη_8. These symmetries remain entangled in four-body wave function even after separation into two mesons. Strong Pauli suppression in tree transitions to KπKπ which has only a small V=2 component and is mainly V=1. No Pauli suppression in transitions to I=2 ππππ state with also two uu quarks but different color-spin couplings. Standard definition of independent color favored and suppressed tree diagrams in B±→KπB^\pm\rightarrow Kπ decays neglects uuuu Pauli entanglement.

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