Non-freeness of groups generated by two parabolic elements with small rational parameters

preprint2020arXivOpen access

Abstract

Let q∈Cq\in\mathbb{C}, let a=(1011),bq=(1q01),a=\begin{pmatrix} 1&0\\1&1\end{pmatrix},\quad b_q=\begin{pmatrix} 1&q\\0&1\end{pmatrix}, and let Gq<SL2(C)G_q<\mathrm{SL}_2(\mathbb{C}) be the group generated by aa and bqb_q. In this paper, we study the problem of determining when the group GqG_q is not free for ∣q∣<4|q|<4 rational. We give a robust computational criterion which allows us to prove that if q=s/rq=s/r for ∣s∣≤27|s|\leq 27 then GqG_q is non-free, with the possible exception of s=24s=24. In this latter case, we prove that the set of denominators r∈Nr\in\mathbb{N} for which G24/rG_{24/r} is non-free has natural density 11. For a general numerator s>27s>27, we prove that the lower density of denominators r∈Nr\in \mathbb{N} for which Gs/rG_{s/r} is non-free has a lower bound 1−(1−11s)∏n=1∞(1−4s2n−1). 1- \left(1-\frac{11}{s}\right) \prod_{n=1}^\infty \left(1-\frac{4}{s^{2^n-1}}\right). Finally, we show that for a fixed ss, there are arbitrarily long sequences of consecutive denominators rr such that Gs/rG_{s/r} is non-free. The proofs of some of the results are computer assisted, and Mathematica code has been provided together with suitable documentation.

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