Noether's problem for p-groups with three generators

preprint2013arXivOpen access

Abstract

Let pp be an odd prime and GG be a nonabelian group of order pnp^{n} with the presentation <α,β,γ∣αpa=βpb=γpc=1,[α,γ]=1,[γ,β]=αpr,[α,β]=γpe>,<α,β,γ\mid α^{p^{a}}=β^{p^{b}}=γ^{p^{c}}=1, [α,γ]=1,[γ,β]=α^{p^{r}},[α,β]=γ^{p^{e}}>, where n>a≥b≥c≥1n>a\geq b\geq c\geq 1. Let kk be a field containing a primitive pap^{a}-th root of unity and GG act on the rational function field k(xh:h∈G)k(x_{h}:h\in G) by g⋅xh=xghg\cdot x_{h}=x_{gh} for all g,h∈Gg,h\in G. In this note, we prove that the fixed field k(G)=k(xh:h∈G)Gk(G)=k(x_{h}:h\in G)^{G} is rational over kk. As a corollary, we prove that if kk contains a primitive p4p^{4}-th root of unity and GG is a nonabelian group of order p5p^{5} generated by three elements, then k(G)k(G) is rational over kk.

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