Abstract
We show that for certain integers , the problem of whether or not a Cayley digraph of is also isomorphic to a Cayley digraph of some other abelian group of order reduces to the question of whether or not a natural subgroup of the full automorphism group contains more than one regular abelian group up to isomorphism (as opposed to the full automorphism group). A necessary and sufficient condition is then given for such circulants to be isomorphic to Cayley digraphs of more than one abelian group, and an easy-to-check necessary condition is provided.
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