An improved Hardy-Trudinger-Moser inequality

Let $\mathbb{B}$ be the unit disc in $\mathbb{R}^2$, $\mathscr{H}$ be the completion of $C_0^\infty(\mathbb{B})$ under the norm $\|u\|_{\mathscr{H}}=\left(\int_\mathbb{B}|\nabla u|^2dx-\int_\mathbb{B}\frac{u^2}{(1-|x|^2)^2}dx\right)^{1/2},\quad\forall u\in C_0^\infty(\mathbb{B}).$ Denote $λ_1(\mathbb{B})=\inf_{u\in \mathscr{H},\,\|u\|_2=1}\|u\|_{\mathscr{H}}^2$, where $\|\cdot\|_2$ stands for the $L^2(\mathbb{B})$-norm. Using blow-up analysis, we prove that for any $α$, $0\leq α<λ_1(\mathbb{B})$, $\sup_{u\in\mathscr{H},\,\|u\|_{\mathscr{H}}^2-α\|u\|_2^2\leq 1}\int_\mathbb{B} e^{4πu^2}dx<+\infty,$ and that the above supremum can be attained by some function $u\in \mathscr{H}$ with $\|u\|_{\mathscr{H}}^2-α\|u\|_2^2= 1$. This improves an earlier result of G. Wang and D. Ye [28].

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