A new elementary proof of the Prime Number Theorem

preprint2021arXivOpen access

Abstract

Let Ω(n)Ω(n) denote the number of prime factors of nn. We show that for any bounded f ⁣:N→Cf\colon\mathbb{N}\to\mathbb{C} one has 1N∑n=1N f(Ω(n)+1)=1N∑n=1N f(Ω(n))+oN→∞(1). \frac{1}{N}\sum_{n=1}^N\, f(Ω(n)+1)=\frac{1}{N}\sum_{n=1}^N\, f(Ω(n))+\mathrm{o}_{N\to\infty}(1). This yields a new elementary proof of the Prime Number Theorem.

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