A Minimum problem for finite sets of real numbers with non-negative sum

preprint2011arXivOpen access

Abstract

Let nn and rr be two integers such that 0<r≤n0 < r \le n; we denote by γ(n,r)γ(n,r) [η(n,r)η(n,r)] the minimum [maximum] number of the non-negative partial sums of a sum ∑1=1nai≥0\sum_{1=1}^n a_i \ge 0, where a1,⋯ ,ana_1, \cdots, a_n are nn real numbers arbitrarily chosen in such a way that rr of them are non-negative and the remaining n−rn-r are negative. Inspired by some interesting extremal combinatorial sum problems raised by Manickam, Miklös and Singhi in 1987 \cite{ManMik87} and 1988 \cite{ManSin88} we study the following two problems: \noindent(P1)(P1) {\it which are the values of γ(n,r)γ(n,r) and η(n,r)η(n,r) for each nn and rr, 0<r≤n0 < r \le n?} \noindent(P2)(P2) {\it if qq is an integer such that γ(n,r)≤q≤η(n,r)γ(n,r) \le q \le η(n,r), can we find nn real numbers a1,⋯ ,ana_1, \cdots, a_n, such that rr of them are non-negative and the remaining n−rn-r are negative with ∑1=1nai≥0\sum_{1=1}^n a_i \ge 0, such that the number of the non-negative sums formed from these numbers is exactly qq?} \noindent We prove that the solution of the problem (P1)(P1) is given by γ(n,r)=2n−1γ(n,r) = 2^{n-1} and η(n,r)=2n−2n−rη(n,r) = 2^n - 2^{n-r}. We provide a partial result of the latter problem showing that the answer is affirmative for the weighted boolean maps. With respect to the problem (P2)(P2) such maps (that we will introduce in the present paper) can be considered a generalization of the multisets a1,⋯ ,ana_1, \cdots, a_n with ∑1=1nai≥0\sum_{1=1}^n a_i \ge 0. More precisely we prove that for each qq such that γ(n,r)≤q≤η(n,r)γ(n,r) \le q \le η(n,r) there exists a weighted boolean map having exactly qq positive boolean values.

Explore this paper’s authors, topics and related work.

Building this map preview

BZPEER is loading the nearby papers, people, topics and institutions for this page.

Reviews 0

Write a reviewWrite

No reviews yet.

Discussion 0

Add a commentWrite

No comments yet.