Abstract

A natural question about Dedekind sums is to find conditions on the integers a1,a2a_1, a_2, and bb such that s(a1,b)=s(a2,b)s(a_1,b) = s(a_2, b). We prove that if the former equality holds then b ∣ (a1a2−1)(a1−a2) b \ | \ (a_1a_2-1)(a_1-a_2). Surprisingly, to the best of our knowledge such statements have not appeared in the literature. A similar theorem is proved for the more general Dedekind-Rademacher sums as well, namely that for any fixed non-negative integer nn, a positive integer modulus bb, and two integers a1a_1 and a2a_2 that are relatively prime to bb, the hypothesis rn(a1,b)=rn(a2,b)r_n (a_1,b)= r_n (a_2,b) implies that b ∣ (6n2+1−a1a2)(a2−a1)b \ | \ (6n^2+1-a_1a_2)(a_2-a_1).

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