Abstract

The rate for complete two-photon annihilation of molecular positronium Ps2_{2} is reported. This decay channel involves a four-body collision among the fermions forming Ps2_{2}, and two photons of 1.022 MeV, each, as the final state. The quantum electrodynamics result for the rate of this process is found to be ΓPs2→γγΓ_{Ps_{2} \rightarrow γγ} = 9.0 ×10−12\times 10^{-12} s−1^{-1}. This decay channel completes the most comprehensive decay chart for Ps2_{2} up to date.

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