Abstract

A fooling-set matrix has nonzero diagonal, but at least one in every pair of diagonally opposite entries is 0. Dietzfelbinger et al. '96 proved that the rank of such a matrix is at least n\sqrt n. It is known that the bound is tight (up to a multiplicative constant). We ask for the "typical" minimum rank of a fooling-set matrix: For a fooling-set zero-nonzero pattern chosen at random, is the minimum rank of a matrix with that zero-nonzero pattern over a field F\mathbb F closer to its lower bound n\sqrt{n} or to its upper bound nn? We study random patterns with a given density pp, and prove an Ω(n)Ω(n) bound for the cases when: (a) pp tends to 00 quickly enough, (b) pp tends to 00 slowly, and ∣F∣=O(1)|\mathbb F|=O(1), (c) p∈(0,1]p\in(0,1] is a constant. We have to leave open the case when p→0p\to 0 slowly and F\mathbb F is a large or infinite field (e.g., F=GF(2n)\mathbb F=GF(2^n), F=RF=\mathbb{R}).

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