The largest left quotient ring of a ring

preprint2011arXivOpen access

Abstract

The left quotient ring (i.e. the left classical ring of fractions) Qcl(R)Q_{cl}(R) of a ring RR does not always exist and still, in general, there is no good understanding of the reason why this happens. In this paper, it is proved existence of the largest left quotient ring Ql(R)Q_l(R), i.e. Ql(R)=S0(R)−1RQ_l(R) = S_0(R)^{-1}R where S0(R)S_0(R) is the largest left regular denominator set of RR. It is proved that Ql(Ql(R))=Ql(R)Q_l(Q_l(R))=Q_l(R); the ring Ql(R)Q_l(R) is semi-simple iff Qcl(R)Q_{cl}(R) exists and is semi-simple; moreover, if the ring Ql(R)Q_l(R) is left artinian then Qcl(R)Q_{cl}(R) exists and Ql(R)=Qcl(R)Q_l(R) = Q_{cl}(R). The group of units Ql(R)∗Q_l(R)^* of Ql(R)Q_l(R) is equal to the set {s−1t ∣ s,t∈S0(R)}\{s^{-1} t\, | \, s,t\in S_0(R)\} and S0(R)=R∩Ql(R)∗S_0(R) = R\cap Q_l(R)^*. If there exists a finitely generated flat left RR-module which is not projective then Ql(R)Q_l(R) is not a semi-simple ring. We extend slightly Ore's method of localization to localizable left Ore sets, give a criterion of when a left Ore set is localizable, and prove that all left and right Ore sets of an arbitrary ring are localizable (not just denominator sets as in Ore's method of localization). Applications are given for certain classes of rings (semi-prime Goldie rings, Noetherian commutative rings, the algebra of polynomial integro-differential operators).

Explore this paper’s authors, topics and related work.

Building this map preview

BZPEER is loading the nearby papers, people, topics and institutions for this page.

Reviews 0

Write a reviewWrite

No reviews yet.

Discussion 0

Add a commentWrite

No comments yet.