Abstract

We present an elegant exact formula for the gaugino ββ-function in a softly-broken supersymmetric gauge theory, of the form βM=O(βg/g)β_M = {\cal O}(β_g/g), where βgβ_g is the gauge ββ function and O{\cal O} is a simple differential operator acting on the gauge coupling gg and the Yukawa coupling.

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