The distance from a point to its opposite along the surface of a box

preprint2015arXivOpen access

Abstract

Given a point (the "spider") on a rectangular box, we would like to find the minimal distance along the surface to its opposite point (the "fly" - the reflection of the spider across the center of the box). Without loss of generality, we can assume that the box has dimensions 1×a×b1\times a\times b with the spider on one of the 1×a1\times a faces (with a≤1a\leq 1). The shortest path between the points is always a line segment for some planar flattening of the box by cutting along edges. We then partition the 1×a1\times a face into regions, depending on which faces this path traverses. This choice of faces determines an algebraic distance formula in terms of aa, bb, and suitable coordinates imposed on the face. We then partition the set of pairs (a,b)(a,b) by homeomorphism of the borders of the 1×a1\times a face's regions and a labeling of these regions.

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