Abstract

Let d≥2d\geq 2, A⊂ZdA \subset \mathbb{Z}^d be finite and not contained in a translate of any hyperplane, and q∈Zq \in \mathbb{Z} such that ∣q∣>1|q| > 1. We show ∣A+q⋅A∣≥(∣q∣+d+1)∣A∣−Oq,d(1).|A+ q \cdot A| \geq (|q|+d+1)|A| - O_{q,d}(1).

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