Abstract

We prove the following sharp estimate for the number of spanning trees of a graph in terms of its vertex-degrees: a simple graph GG on nn vertices has at most (1/n2)∏v∈V(G)(d(v)+1)(1/n^{2}) \prod_{v \in V(G)} (d(v)+1) spanning trees. This result is tight (for complete graphs), and improves earlier estimates of Alon from 1990 and Kostochka from 1995 by a factor of about 1/n1/n (for dense graphs). We additionally show that an analogous bound holds for the weighted spanning tree enumerator of a (nonnegatively) weighted graph as well.

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