Abstract
Motivated by a path planning problem we consider the following procedure. Assume that we have two points and in the plane and take . At each step we add to a compact convex set that does not contain nor . The procedure terminates when the sets in separate and . We show how to add one set to in amortized time plus the time needed to find all sets of intersecting the newly added set, where is the cardinality of , is the number of sets in intersecting the newly added set, and is the inverse of the Ackermann function.
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