Abstract

We consider the following qq-analog of the basic combinatorial search problem: let qq be a prime power and $\GF(q)$ the finite field of qq elements. Let VV denote an nn-dimensional vector space over $\GF(q)$ and let v\mathbf{v} be an unknown 1-dimensional subspace of VV. We will be interested in determining the minimum number of queries that is needed to find v\mathbf{v} provided all queries are subspaces of VV and the answer to a query UU is YES if v⩽U\mathbf{v} \leqslant U and NO if v⩽̸U\mathbf{v} \not\leqslant U. This number will be denoted by A(n,q)A(n,q) in the adaptive case (when for each queries answers are obtained immediately and later queries might depend on previous answers) and M(n,q)M(n,q) in the non-adaptive case (when all queries must be made in advance). In the case n=3n=3 we prove 2q−1=A(3,q)<M(3,q)2q-1=A(3,q)<M(3,q) if qq is large enough. While for general values of nn and qq we establish the bounds nlog⁡q≤A(n,q)≤(1+o(1))nq n\log q \le A(n,q) \le (1+o(1))nq and (1−o(1))nq≤M(n,q)≤2nq, (1-o(1))nq \le M(n,q) \le 2nq, provided qq tends to infinity.

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