Abstract

We study a magnetic molecule that exhibits spin tunneling and is free to rotate about its anisotropy axis. Exact low-energy eigenstates of the molecule that are superpositions of spin and rotational states are obtained. We show that parameter α=2(ℏS)2/(IΔ)α= 2(\hbar S)^2/(IΔ) determines the ground state of the molecule. Here ℏS\hbar S is the spin, II is the moment of inertia, and ΔΔ is the tunnel splitting. The magnetic moment of the molecule is zero at α<αc=[1−1/(2S)2]−1α< α_c = [1-1/(2S)^{2}]^{-1} and non-zero at α>αcα> α_c. At α→∞α\to \infty the spin of the molecule localizes in one of the directions along the anisotropy axis.

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