Orbit equivalence, coinduced actions and free products

The following result is proven. Let $G_1 \cc^{T_1} (X_1,μ_1)$ and $G_2 \cc^{T_2} (X_2,μ_2)$ be orbit-equivalent, essentially free, probability measure preserving actions of countable groups $G_1$ and $G_2$. Let $H$ be any countable group. For $i=1,2$, let $Γ_i = G_i *H$ be the free product. Then the actions of $Γ_1$ and $Γ_2$ coinduced from $T_1$ and $T_2$ are orbit-equivalent. As an application, it is shown that if $Γ$ is a free group, then all nontrivial Bernoulli shifts over $Γ$ are orbit-equivalent.

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