Abstract

We consider the largest number of minimal separators a graph on n vertices can have at most. We give a new proof that this number is in O(((1+5)/2)nn)O( ((1+\sqrt{5})/2)^n n ). We prove that this number is in ω(1.4521n)ω( 1.4521^n ), improving on the previous best lower bound of Ω(3n/3)⊆ω(1.4422n)Ω(3^{n/3}) \subseteq ω( 1.4422^n ). This gives also an improved lower bound on the number of potential maximal cliques in a graph. We would like to emphasize that our proofs are short, simple, and elementary.

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