Abstract
Given non-negative integers , the Hamilton-Waterloo problem asks for a factorization of the complete graph into -factors and -factors. Clearly, odd, , , and are necessary conditions. To date results have only been found for specific values of and . In this paper we show that for any and the necessary conditions are sufficient when is a multiple of and , except possibly when or 3, with five additional possible exceptions in . For the case where we show sufficiency when except possibly when , , with seven further possible exceptions in . We also show that when are odd integers, the lexicographic product of with the empty graph of order has a factorization into -factors and -factors for every , , except possibly when , , with three additional possible exceptions in .
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