On the divisibility of an±bna^n \pm b^n by powers of nn

preprint2013arXivOpen access

Abstract

We determine all triples (a,b,n)(a,b,n) of positive integers such that aa and bb are relatively prime and nkn^k divides an+bna^n + b^n (respectively, an−bna^n - b^n), when kk is the maximum of aa and bb (in fact, we answer a slightly more general question). As a by-product, it is found that, for m,n∈N+m, n \in \mathbb N^+ with n≥2n \ge 2, nmn^m divides mn+1 m^n + 1 if and only if (m,n)=(2,3)(m,n)=(2,3) or (1,2)(1,2), which generalizes problems from the 1990 and 1999 editions of the International Mathematical Olympiad. The results are related to a conjecture by K. Győry and C. Smyth on the finiteness of the sets Rk±(a,b):={n∈N+:nk∣an±bn}R_k^\pm(a,b) := \{n \in \mathbb N^+: n^k \mid a^n \pm b^n\}, when a,b,ka,b,k are fixed integers with k≥3k \ge 3, gcd⁡(a,b)=1\gcd(a,b) = 1 and ∣ab∣≥2|ab| \ge 2.

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