On the congruence 1m+2m+⋯+mm≡n(modm)1^m + 2^m + \dotsb + m^m \equiv n \pmod{m} with n∣mn | m

preprint2014arXivOpen access

Abstract

We show that if the congruence above holds and n∣mn\mid m, then the quotient Q:=m/nQ:=m/n satisfies ∑p∣QQp+1≡0(modQ)\sum_{p\mid Q} \frac{Q}{p}+1 \equiv 0\pmod{Q}, where pp is prime. The only known solutions of the latter congruence are Q=1Q=1 and the eight known primary pseudoperfect numbers 2,6,42,1806,47058,2214502422,52495396602,2,6,42, 1806, 47058, 2214502422, 52495396602, and 84904215835596884107067712610868490421583559688410706771261086. Fixing QQ, we prove that the set of positive integers nn satisfying the congruence in the title, with m=Qnm=Q n, is empty in case Q=52495396602Q=52495396602, and in the other eight cases has an asymptotic density between bounds in (0,1)(0,1) that we provide.

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