On some mean value results for the zeta-function and a divisor problem II

preprint2015arXivOpen access

Abstract

Let d(n)d(n) be the number of divisors of nn, let γγ denote Euler's constant and Δ(x):=∑n≤xd(n)−x(log⁡x+2γ−1) Δ(x) := \sum_{n\le x}d(n) - x(\log x + 2γ-1) denote the error term in the classical Dirichlet divisor problem, and let ζ(s)ζ(s) denote the Riemann zeta-function. It is shown that ∫0TΔ(t)∣ζ(1/2+it)∣2 dt≪T(log⁡T)4. \int_0^TΔ(t)|ζ(1/2+it)|^2\,dt \ll T(\log T)^{4}. Further, if 2≤k≤82\le k\le 8 is a fixed integer, then we prove the asymptotic formula ∫1TΔk(t)∣ζ(1/2+it)∣2 dt=c1(k)T1+k4log⁡T+c2(k)T1+k4+Oε(T1+k4−ηk+ε), \int_1^{T}Δ^{k}(t)|ζ(1/2+it)|^2\,dt=c_1(k)T^{1+\frac k4}\log T+ c_2(k)T^{1+\frac k4}+O_\varepsilon(T^{1+\frac k4-η_k+\varepsilon}), where c1(k)c_1(k) and c2(k)c_2(k) are explicit constants, and where η2=3/20,η3=η4=1/10, η5=3/80, η6=35/4742, η7=17/6312, η8=8/9433.η_2= 3/20, η_3= η_4=1/10,\ η_5=3/80,\ η_6=35/4742,\ η_7=17/6312,\ η_8=8/9433. The results depend on the power moments of Δ(t)Δ(t) and E(T)E(T), the classical error term in the asymptotic formula for the mean square of ∣ζ(1/2+it)∣|ζ(1/2+it)|.

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