On some mean value results for the zeta-function and a divisor problem

preprint2014arXivOpen access

Abstract

Let Δ(x)Δ(x) denote the error term in the classical Dirichlet divisor problem, and let the modified error term in the divisor problem be Δ∗(x)=−Δ(x)+2Δ(2x)−12Δ(4x)Δ^*(x) = -Δ(x) + 2Δ(2x) - \frac{1}{2}Δ(4x). We show that ∫TT+HΔ∗(t2π)∣ζ(1/2+it)∣2dt  ≪  HT1/6log⁡7/2T(T2/3+ε≤H=H(T)≤T), \int_T^{T+H}Δ^*\bigl(\frac{t}{2π}\bigr)|ζ(1/2+it)|^2dt \;\ll\; HT^{1/6}\log^{7/2}T \quad(T^{2/3+\varepsilon} \le H = H(T) \le T), ∫0TΔ(t)∣ζ(1/2+it)∣2dt  ≪  T9/8(log⁡T)5/2, \int_0^TΔ(t)|ζ(1/2+it)|^2dt \;\ll\; T^{9/8}(\log T)^{5/2}, and obtain asymptotic formulae for ∫0T(Δ∗(t2π))2∣ζ(1/2+it)∣2dt,∫0T(Δ∗(t2π))3∣ζ(1/2+it)∣2dt. \int_0^T{\Bigl(Δ^*\bigl(\frac{t}{2π}\bigr)\Bigr)}^2 |ζ(1/2+it)|^2dt,\quad \int_0^T{\Bigl(Δ^*\bigl(\frac{t}{2π}\bigr)\Bigr)}^3|ζ(1/2+it)|^2dt. The importance of the Δ∗Δ^*-function comes from the fact that it is the analogue of E(T)E(T), the error term in the mean square formula for ∣ζ(1/2+it)∣2|ζ(1/2+it)|^2. We also show, if E∗(T):=E(T)−2πΔ∗(T/(2π))E^*(T) := E(T) - 2πΔ^*(T/(2π)), ∫0TE∗(t)Ej(t)∣ζ(1/2+it)∣2dt  ≪j,ε  T7/6+j/4+ε(j=1,2,3). \int_0^T E^*(t)E^j(t)|ζ(1/2+it)|^2dt \; \ll_{j,\varepsilon}\; T^{7/6+j/4+\varepsilon}\quad(j= 1,2,3).

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