Abstract

A ring RR is feckly clean provided that for any a∈Ra\in R there exists an element e∈Re\in R and a full element u∈Ru\in R such that a=e+u,eR(1−e)⊆J(R)a=e+u, eR(1-e)\subseteq J(R). We prove that a ring RR is feckly clean if and only if for any a∈Ra\in R, there exists an element e∈Re\in R such that V(a)⊆V(e),V(1−a)⊆V(1−e)V(a)\subseteq V(e), V(1-a)\subseteq V(1-e) and eR(1−e)⊆J(R)eR(1-e)\subseteq J(R), if and only if for any distinct maximal ideals MM and NN, there exists an element e∈Re\in R such that e∈M,1−e∈Ne\in M, 1-e\in N and eR(1−e)⊆J(R)eR(1-e)\subseteq J(R), if and only if JJ-spec(R)spec(R) is strongly zero dimensional, if and only if Max(R)Max(R) is strongly zero dimensional and every prime ideal containing J(R)J(R) is contained in a unique maximal ideal. More explicit characterizations are also discussed for commutative feckly clean rings.

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