On equivalence relations induced by Polish groups

preprint2024arXivOpen access

Abstract

The motivation of this article is to introduce a kind of orbit equivalence relations which can well describe structures and properties of Polish groups from the perspective of Borel reducibility. Given a Polish group GG, let E(G)E(G) be the right coset equivalence relation Gω/c(G)G^ω/c(G), where c(G)c(G) is the group of all convergent sequences in GG. Let GG be a Polish group. (1) GG is a discrete countable group containing at least two elements iff E(G)∼BE0E(G)\sim_BE_0; (2) if GG is TSI uncountable non-archimedean, then E(G)∼BE0ωE(G)\sim_BE_0^ω; (3) GG is non-archimedean iff E(G)≤B=+E(G)\le_B=^+; (4) if HH is a CLI Polish group but GG is not, then E(G)̸≤BE(H)E(G)\not\le_BE(H); (5) if HH is a non-archimedean Polish group but GG is not, then E(G)̸≤BE(H)E(G)\not\le_BE(H). The notion of αα-l.m.-unbalanced Polish group for α<ω1α<ω_1 is introduced. Let G,HG,H be Polish groups, 0<α<ω10<α<ω_1. If GG is αα-l.m.-unbalanced but HH is not, then E(G)̸≤BE(H)E(G)\not\le_B E(H). For TSI Polish groups, the existence of Borel reduction is transformed into the existence of a well-behaved continuous mapping between topological groups. As its applications, for any Polish group GG, let G0G_0 be the connected component of the identity element 1G1_G. Let GG and HH be two separable TSI Lie groups. If E(G)≤BE(H)E(G)\le_BE(H), then there exists a continuous locally injective map S:G0→H0S:G_0\to H_0. Moreover, if G0,H0G_0,H_0 are abelian, SS is a group homomorphism. In particular, for c0,e0,c1,e1∈Nc_0,e_0,c_1,e_1\in{\mathbb N}, E(Rc0×Te0)≤BE(Rc1×Te1)E({\mathbb R}^{c_0}\times{\mathbb T}^{e_0})\le_BE({\mathbb R}^{c_1}\times{\mathbb T}^{e_1}) iff e0≤e1e_0\le e_1 and c0+e0≤c1+e1c_0+e_0\le c_1+e_1.

Explore this paper’s authors, topics and related work.

Building this map preview

BZPEER is loading the nearby papers, people, topics and institutions for this page.

Reviews 0

Write a reviewWrite

No reviews yet.

Discussion 0

Add a commentWrite

No comments yet.