On a conjectural congruence of Guo

preprint2020arXivOpen access

Abstract

Let p≡3(mod4)p\equiv3\pmod{4} be a prime and rr a positive integer. We show that ∏k=1(p2r−1)/24k−14k+1≡1(modp2). \prod_{k=1}^{(p^{2r}-1)/2}\frac{4k-1}{4k+1}\equiv1\pmod{p^2}. This confirms a recent conjecture of Guo.

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