Abstract

A nondecreasing sequence of positive integers is (α,β)(α,β)-Conolly, or Conolly-like for short, if for every positive integer mm the number of times that mm occurs in the sequence is α+βrmα+ βr_m, where rmr_m is 11 plus the 2-adic valuation of mm. A recurrence relation is (α,β)(α, β)-Conolly if it has an (α,β)(α, β)-Conolly solution sequence. We discover that Conolly-like sequences often appear as solutions to nested (or meta-Fibonacci) recurrence relations of the form A(n)=∑i=1kA(n−si−∑j=1piA(n−aij))A(n) = \sum_{i=1}^k A(n-s_i-\sum_{j=1}^{p_i} A(n-a_{ij})) with appropriate initial conditions. For any fixed integers kk and p1,p2,…,pkp_1,p_2,\ldots, p_k we prove that there are only finitely many pairs (α,β)(α, β) for which A(n)A(n) can be (α,β)(α, β)-Conolly. For the case where α=0α=0 and β=1β=1, we provide a bijective proof using labelled infinite trees to show that, in addition to the original Conolly recurrence, the recurrence H(n)=H(n−H(n−2))+H(n−3−H(n−5))H(n)=H(n-H(n-2)) + H(n-3-H(n-5)) also has the Conolly sequence as a solution. When k=2k=2 and p1=p2p_1=p_2, we construct an example of an (α,β)(α,β)-Conolly recursion for every possible (α,β)α,β) pair, thereby providing the first examples of nested recursions with pi>1p_i>1 whose solutions are completely understood. Finally, in the case where k=2k=2 and p1=p2p_1=p_2, we provide an if and only if condition for a given nested recurrence A(n)A(n) to be (α,0)(α,0)-Conolly by proving a very general ceiling function identity.

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