Abstract

We prove that the number of monomer-dimer tilings of an n×nn\times n square grid, with m<nm<n monomers in which no four tiles meet at any point is m2m+(m+1)2m+1m2^m+(m+1)2^{m+1}, when mm and nn have the same parity. In addition, we present a new proof of the result that there are n2n−1n2^{n-1} such tilings with nn monomers, which divides the tilings into nn classes of size 2n−12^{n-1}. The sum of these tilings over all monomer counts has the closed form 2n−1(3n−4)+22^{n-1}(3n-4)+2 and, curiously, this is equal to the sum of the squares of all parts in all compositions of nn. We also describe two algorithms and a Gray code ordering for generating the n2n−1n2^{n-1} tilings with nn monomers, which are both based on our new proof.

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