Minimal resistance of curves under the single impact assumption

preprint2014arXivOpen access

Abstract

We consider the hollow on the half-plane {(x,y):y≤0}⊂R2\{(x,y) : y \le 0\} \subset \mathbb{R}^2 defined by a function u:(−1,1)→Ru : (-1, 1) \to \mathbb{R}, u(x)<0u(x) < 0 and a vertical flow of point particles incident on the hollow. It is assumed that uu satisfies the so-called single impact condition (SIC): each incident particle is elastically reflected by graph(u)(u) and goes away without hitting the graph of uu anymore. We solve the problem: find the function uu minimizing the force of resistance created by the flow. We show that the graph of the minimizer is formed by two arcs of parabolas symmetric to each other with respect to the yy-axis. Assuming that the resistance of u≡0u \equiv 0 equals 1, we show that the minimal resistance equals π/2−2arctan⁡(1/2)≈0.6435π/2 - 2\arctan(1/2) \approx 0.6435. This result completes the previously obtained result stating in particular that the minimal resistance of a hollow in higher dimensions equals 0.5. We additionally consider a similar problem of minimal resistance, where the hollow in the half-space {(x1,…,xd,y):y≤0}⊂Rd+1\{(x_1,\ldots,x_d, y) : y \le 0 \} \subset \mathbb{R}^{d+1} is defined by a radial function UU satisfying SIC, U(x)=u(∣x∣)U(x) = u(|x|), with x=(x1,…,xd),u(ξ)<0x = (x_1,\ldots,x_d), u(ξ) < 0 for 0≤ξ<10 \le ξ< 1 and u(ξ)=0u(ξ) = 0 for ξ≥1ξ\ge 1, and the flow is parallel to the yy-axis. The minimal resistance is greater than 0.50.5 (and coincides with 0.64350.6435 when d=1d = 1) and converges to 0.50.5 as d→∞d \to \infty.

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