Maker-Breaker Percolation Games I: Crossing Grids

preprint2020arXivOpen access

Abstract

Motivated by problems in percolation theory, we study the following 2-player positional game. Let Λm×nΛ_{m \times n} be a rectangular grid-graph with mm vertices in each row and nn vertices in each column. Two players, Maker and Breaker, play in alternating turns. On each of her turns, Maker claims pp (as-yet unclaimed) edges of the board Λm×nΛ_{m \times n}, while on each of his turns Breaker claims qq (as-yet unclaimed) edges of the board and destroys them. Maker wins the game if she manages to claim all the edges of a crossing path joining the left-hand side of the board to its right-hand side, otherwise Breaker wins. We call this game the (p,q)(p,q)-crossing game on Λm×nΛ_{m \times n}. Given m,n∈Nm,n\in \mathbb{N}, for which pairs (p,q)(p,q) does Maker have a winning strategy for the (p,q)(p,q)-crossing game on Λm×nΛ_{m \times n}? The (1,1)(1,1)-case corresponds exactly to the popular game of Bridg-it, which is well understood due to it being a special case of the older Shannon switching game. In this paper, we study the general (p,q)(p,q)-case. Our main result is to establish the following transition: ∙\bullet If p⩾2qp\geqslant 2q, then Maker wins the game on arbitrarily long versions of the narrowest board possible, i.e. Maker has a winning strategy for the (2q,q)(2q, q)-crossing game on Λm×(q+1)Λ_{m \times(q+1)} for any m∈Nm\in \mathbb{N}; ∙\bullet if p⩽2q−1p\leqslant 2q-1, then for every width nn of the board, Breaker has a winning strategy for the (p,q)(p,q)-crossing game on Λm×nΛ_{m \times n} for all sufficiently large board-lengths mm. Our winning strategies in both cases adapt more generally to other grids and crossing games. In addition we pose many new questions and problems.

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