Abstract

We give lower bounds for the problem of stable sparse recovery from /adaptive/ linear measurements. In this problem, one would like to estimate a vector x∈Rnx \in \R^n from mm linear measurements A1x,...,AmxA_1x,..., A_mx. One may choose each vector AiA_i based on A1x,...,Ai−1xA_1x,..., A_{i-1}x, and must output x∗x* satisfying |x* - x|_p \leq (1 + ε) \min_{k\text{-sparse} x'} |x - x'|_p with probability at least 1−δ>2/31-δ>2/3, for some p∈{1,2}p \in \{1,2\}. For p=2p=2, it was recently shown that this is possible with m=O(1εklog⁡log⁡(n/k))m = O(\frac{1}εk \log \log (n/k)), while nonadaptively it requires Θ(1εklog⁡(n/k))Θ(\frac{1}εk \log (n/k)). It is also known that even adaptively, it takes m=Ω(k/ε)m = Ω(k/ε) for p=2p = 2. For p=1p = 1, there is a non-adaptive upper bound of O~(1εklog⁡n)\tilde{O}(\frac{1}{\sqrtε} k\log n). We show: * For p=2p=2, m=Ω(log⁡log⁡n)m = Ω(\log \log n). This is tight for k=O(1)k = O(1) and constant εε, and shows that the log⁡log⁡n\log \log n dependence is correct. * If the measurement vectors are chosen in RR "rounds", then m=Ω(Rlog⁡1/Rn)m = Ω(R \log^{1/R} n). For constant εε, this matches the previously known upper bound up to an O(1) factor in RR. * For p=1p=1, m=Ω(k/(ε⋅log⁡k/ε))m = Ω(k/(\sqrtε \cdot \log k/ε)). This shows that adaptivity cannot improve more than logarithmic factors, providing the analog of the m=Ω(k/ε)m = Ω(k/ε) bound for p=2p = 2.

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