How would Riemann evaluate $ζ(2n)$ ?

preprint2012arXivOpen access

Commenting on an observation of Prof. Edwards, this note presents a method of evaluation of $ζ(2n)$ that follows easily from Riemann's own representation of the zeta function.

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How would Riemann evaluate $ζ(2n)$ ?

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How would Riemann evaluate ζ(2n)ζ(2n)ζ(2n)?

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How would Riemann evaluate $ζ(2n)$ ?