How to prove that some Bernoulli convolution has the weak Gibbs property

preprint2014arXivOpen access

Abstract

In this paper we give an example of uniform convergence of the sequence of column vectors A1…AnV∥A1…AnV∥\displaystyle{A_1\dots A_nV\over\left\Vert A_1\dots A_nV\right\Vert}, Ai∈{A,B,C}A_i\in\{A,B,C\}, A,B,CA,B,C being some (0,1)(0,1)-matrices of order 77 with much null entries, and VV a fixed positive column vector. These matrices come from the study of the Bernoulli convolution in the base β>1β>1 such that β3=2β2−β+1β^3=2β^2-β+1, that is, the (continuous singular) probability distribution of the random variable (β−1)∑n=1∞ωnβn\displaystyle(β-1)\sum_{n=1}^\infty{ω_n\overβ^n} when the independent random variables ωnω_n take the values 00 and 11 with probability 12\displaystyle{1\over2}. In the last section we deduce, from the uniform convergence of A1…AnV∥A1…AnV∥\displaystyle{A_1\dots A_nV\over\left\Vert A_1\dots A_nV\right\Vert}, the Gibbs and the multifractal properties of this measure.

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