Abstract

For each d>0d>0, we find all the smallest fullerenes for which the least distance between two pentagons is dd. We also show that for each dd there is an hdh_d such that fullerenes with pentagons at least distance dd apart and any number of hexagons greater than or equal to hdh_d exist. We also determine the number of fullerenes where the minimum distance between any two pentagons is at least dd, for 1≤d≤51 \le d \le 5, up to 400 vertices.

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