Abstract
Fix , . A simple argument shows that for each , and almost all (asymptotically 100% of) primes , the multiplicative order of modulo exceeds . It is an open problem to show the same result with replaced by any larger constant. We show that if are multiplicatively independent, then for almost all primes , one of has order exceeding . The same method allows one to produce, for each , explicit finite sets with the property that for almost all primes , some element of has order exceeding . Similar results hold for orders modulo general integers rather than primes .
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