Abstract

In this work, we propose a new scheme to solve the angular Teukolsky equation for the particular case: m=0,s=0m=0, s=0. We first transform this equation to a confluent Heun differential equation and then construct the Wronskian determinant to calculate the eigenvalues and normalized eigenfunctions. We find that the eigenvalues for larger ll are approximately given by 0Al0≈[l(l+1)−τR2/2]−i  τI2/2_{0}{A_{l0}} \approx [l(l + 1) - τ_{R}^2/2] - i\;τ_{I}^2/2 with an arbitrary τ2=τR2+i τI2τ^2=τ_R^2 + i\,τ_{I}^2. The angular probability distribution (APD) for the ground state moves towards the north and south poles for τR2>0τ_R^2>0, but aggregates to the equator for τR2≤0τ_R^2\leq0. However, we also notice that the APD for large angular momentum ll always moves towards the north and south poles , regardless the choice of τ2τ^2.

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