Egyptian Fractions with odd denominators

preprint2016arXivOpen access

Abstract

The number of solutions of the diophantine equation ∑i=1k1xi=1,\sum_{i=1}^k \frac{1}{x_i}=1, in particular when the xix_i are distinct odd positive integers is investigated. The number of solutions S(k)S(k) in this case is, for odd kk: exp⁡(exp⁡(c1 klog⁡k))≤S(k)≤exp⁡(exp⁡(c2 k))\exp \left( \exp \left( c_1\, \frac{k}{\log k}\right)\right) \leq S(k) \leq \exp \left( \exp \left(c_2\, k \right)\right) with some positive constants c1c_1 and c2c_2. This improves upon an earlier lower bound of S(k)≥exp⁡((1+o(1))log⁡22k2)S(k) \geq \exp \left( (1+o(1))\frac{\log 2}{2} k^2\right).

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