Dynamics of continuous maps induced on the space of probability measures

preprint2020arXivOpen access

Abstract

For a continuous self-map ff on a compact interval II and the induced map f^\hat f on the space M(I)\mathcal{M}(I) of probability measures, we obtain a sharp condition to guarantee that (I,f)(I,f) is transitive if and only if (M(I),f^)(\mathcal{M}(I),\hat f) is transitive. We also show that the sensitivity of (I,f)(I,f) is equivalent to that of (M(I),f^)(\mathcal{M}(I),\hat f). We prove that (M(I),f^)(\mathcal{M}(I),\hat f) must have infinite topological entropy for any transitive system (I,f)(I,f), while there exists a transitive non-autonomous system (I,f0,∞)(I,f_{0,\infty}) such that (M(I),f^0,∞)(\mathcal{M}(I),\hat f_{0,\infty}) has zero topological entropy, where f0,∞={fn}n=0∞f_{0,\infty}=\{f_n\}_{n=0}^\infty is a sequence of continuous self-maps on II. For a continuous self-map ff on a general compact metric space XX, we show that chain transitivity of (X,f)(X, f) implies chain mixing of (M(X),f^)(\mathcal{M}(X),\hat f), and we provide two counterexamples to demonstrate that the converse is not true. We confirm that shadowing of (X,f)(X,f) is not inherited by (M(X),f^)(\mathcal{M}(X),\hat f) in general. For a non-autonomous system (X,f0,∞)(X,f_{0,\infty}), we prove that if (M(X),f^0,∞)(\mathcal{M}(X),\hat{f}_{0,\infty}) is weak mixing of order nn, then so is (X,f0,∞)(X,f_{0,\infty}) for any n≥2n\geq2; while there exists (X,f0,∞)(X,f_{0,\infty}) such that it is weak mixing of order 22 but (M(X),f^0,∞)(\mathcal{M} (X),\hat{f}_{0,\infty}) is not. We then prove that Li-Yorke chaos (resp., distributional chaos) of (X,f0,∞)(X,f_{0,\infty}) carries over to (M(X),f^0,∞)(\mathcal{M}(X),\hat f_{0,\infty}), and give an example to show that (X,f)(X,f) and (M(X),f^)(\mathcal{M}(X),\hat f) may have no Li-Yorke pair simultaneously. We also prove that if fnf_n is surjective for all n≥0n\geq 0, then chain mixing of (M(X),f^0,∞)(\mathcal{M}(X),\hat f_{0,\infty}) always holds true, and shadowing of (M(X),f^0,∞)(\mathcal{M}(X),\hat f_{0,\infty}) implies mixing of (X,f0,∞)(X, f_{0,\infty}).

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