Conjectures and results on x2x^2 mod p2p^2 with 4p=x2+dy24p=x^2+dy^2

preprint2014arXivOpen access

Abstract

Given a squarefree positive integer dd, we want to find integers (or rational numbers with denominators not divisible by large primes) a0,a1,a2,…a_0,a_1,a_2,\ldots such that for sufficiently large primes pp we have ∑k=0p−1ak≡x2−2p\sum_{k=0}^{p-1}a_k\equiv x^2-2p (mod p2p^2) if 4p=x2+dy24p=x^2+dy^2 (and 4∤x4\nmid x if d=1d=1), and ∑k=0p−1ak≡0\sum_{k=0}^{p-1}a_k\equiv 0 (mod p2p^2) if (−dp)=−1(\frac{-d}p)=-1. In this paper we give a survey of conjectures and results on this topic and point out the connection between this problem and series for 1/π1/π.

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